Superscript termination

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  • #44581
    j.l.ceja760
    Participant

    <p data-start="0" data-end="6">Hello,</p>
    <p data-start="8" data-end="78">UEB 11.4.1 defines an item in several bullet points. The first states:</p>

    <p data-start="82" data-end="286">“An entire number, i.e., the initiating numeric symbol and all succeeding symbols within the numeric mode thus established (which would include decimal points, commas, and simple numeric fraction lines).”</p>

    <p data-start="288" data-end="444">With that in mind, is it acceptable to terminate the first numeric symbol with a numeric terminator and then begin a new numeric symbol (not superscripted)?</p>
    <p data-start="446" data-end="849">Here is the issue: I have a superscript number that is immediately followed by a regular number, with no space between them. My proposed solution is to insert a numeric terminator (or a grade 1 terminator), then repeat the numeric indicator before the regular number to begin a new item. Is this the correct approach? I have not been able to find any guidance that specifically addresses this situation.</p>
    <p data-start="851" data-end="913" data-is-last-node="" data-is-only-node="">I have attached both print and braille examples for reference.</p>
     

     

     

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    #44585
    James Williams
    Moderator

    Thank you for your question. The solution to your situation lies in the definition of an item that you mentioned, specifically the statement "An entire number, i.e., the initiating numeric symbol and all succeeding symbols within the numeric mode thus established".

    Using this definition as a guideline, you do not need to use a numeric terminator or a grade one terminator; you would only use a numeric indicator to start the 490 at the baseline immediately following the superscript 10. The thought process here is similar to a mixed number where the whole number is followed immediately by the fractional part starting with its numeric indicator. I have attached a file including both the Simbraille and ASCII for the proposed solution.

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    #44588
    j.l.ceja760
    Participant

    Thanks James.

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