Reply To: Hypercomplex fraction with cancellation

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#20547
Chris Clemens
Keymaster

Hi Barbara. I think your equation is a complex fraction rather than hypercomplex. The numerator and denominator each contain simple fractions. Cancellation in fractions requires a spatial presentation instead of linear. I have attached a suggestion for this problem along with my print version of the fraction you described. Let me know if I have interpreted your description incorrectly.